Functions Question Watch

toby_ling
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#1
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Not sure about this!? :eek3:

If f(x) is even and g(x) is odd, prove that fg(x) is even. [2 marks]
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sonofdot
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#2
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fg(-x) = f(g(-x)) = ...
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brodiebro
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Start by saying f(x)=2x and g(x)= 2x + 1
Then go on from there
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toby_ling
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(Original post by sonofdot)
fg(-x) = f(g(-x)) = ...
Ok, fg(-x) = f(g(-x)) = f(-g(x)) = ... then what? :confused:
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generalebriety
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(Original post by toby_ling)
Ok, fg(-x) = f(g(-x)) = f(-g(x)) = ... then what? :confused:
Let g(x) = y. Compare f(-y) and f(y)...
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generalebriety
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(Original post by brodiebro)
Start by saying f(x)=2x and g(x)= 2x + 1
Then go on from there
I think you've misunderstood 'even' and 'odd' in this context.
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