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# Functions Question watch

If f(x) is even and g(x) is odd, prove that fg(x) is even. [2 marks]
2. fg(-x) = f(g(-x)) = ...
3. Start by saying f(x)=2x and g(x)= 2x + 1
Then go on from there
4. (Original post by sonofdot)
fg(-x) = f(g(-x)) = ...
Ok, fg(-x) = f(g(-x)) = f(-g(x)) = ... then what?
5. (Original post by toby_ling)
Ok, fg(-x) = f(g(-x)) = f(-g(x)) = ... then what?
Let g(x) = y. Compare f(-y) and f(y)...
6. (Original post by brodiebro)
Start by saying f(x)=2x and g(x)= 2x + 1
Then go on from there
I think you've misunderstood 'even' and 'odd' in this context.

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Updated: January 23, 2010
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