A wire is bent into shape ABCDE. ABDE is a rectangle and BCD is a semicircle with diameter BD. The area of the region enclosed is R m^2. AE = x metres and and AB = ED = y metres. The total lennth of the wire is 2m
a) Find an expression fo y in terms of x.
Ive sketched it and put:
Perimeter = x + y + (2TTr)/2 = 2
Perimeter = x + y + (2TTx/2)/2 = 2
The answer says: y = 1 - x/2 = TTx/4
How do you get to that?!
Thanks for any help.
Differentiation help!!!!!!! watch
- Thread Starter
- 23-01-2010 23:26
Offline14ReputationRep:Wiki Support Team
- Wiki Support Team
- 23-01-2010 23:55
x + 2y + pi*x/2 = 2 - don't forget to include both sides AB and DE. Rearrange for y.