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    A wire is bent into shape ABCDE. ABDE is a rectangle and BCD is a semicircle with diameter BD. The area of the region enclosed is R m^2. AE = x metres and and AB = ED = y metres. The total lennth of the wire is 2m

    a) Find an expression fo y in terms of x.

    Ive sketched it and put:

    Perimeter = x + y + (2TTr)/2 = 2

    Perimeter = x + y + (2TTx/2)/2 = 2

    The answer says: y = 1 - x/2 = TTx/4

    How do you get to that?!

    Thanks for any help.
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    x + 2y + pi*x/2 = 2 - don't forget to include both sides AB and DE. Rearrange for y.
 
 
 
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Updated: January 23, 2010
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