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    (Original post by someperson)
    i'm too slow with latex:sigh:

    and i'm being dumb...but how do you get the first...i get -2 not -1/2
    :mmm:

    Erm...in what bit?
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    (Original post by maxfire)
    :mmm:

    Erm...in what bit?
    differentiating y=1/2x:o:
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    hmm yh i got up to x^5/2 = 1/32

    i dont know how to do it from there :/

    thanks for all the help
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    (Original post by uxa595)
    hmm yh i got up to x^5/2 = 1/32

    i dont know how to do it from there :/

    thanks for all the help
    how else can you write x^5/2 ?
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    oh i got it x=1/2
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    (Original post by uxa595)
    oh i got it x=1/2
    i dont think that's right...write out your steps
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    (Original post by someperson)
    differentiating y=1/2x:o:
    y=\frac{1}{2x}=\frac{1}{2}x^{-1}
    \frac{dy}{dx}=\frac{1}{2}\times-x^{-2}=-\frac{1}{2x^{2}}

    Is that what you mean?
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    (Original post by uxa595)
    hmm yh i got up to x^5/2 = 1/32

    i dont know how to do it from there :/

    thanks for all the help
    x^{\frac{5}{2}}=\frac{1}{32}

    x = (x^{\frac{5}{2}})^\frac{2}{5}=(\  frac{1}{32})^\frac{2}{5}

    Do you understand that?
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    (Original post by maxfire)
    y=\frac{1}{2x}=\frac{1}{2}x^{-1}
    \frac{dy}{dx}=\frac{1}{2}\times-x^{-2}=-\frac{1}{2x^{2}}

    Is that what you mean?
    :o: thanks...i just confused myself

    :getmecoat:
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    whats dy/dx of 4x^3/2 ??
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    (Original post by uxa595)
    whats dy/dx of 4x^3/2 ??
    6x^(1/2)
 
 
 
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