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# C2: Further Diff question? watch

1. Find the equation of the tangents to the curve y=(2#x-1)(#x-1)
# means square root btw.

at the points were the curve cuts the x-axis (y=0)

Find the co-ordinates of the points of intersection of these tangents.
2. okay, first find the x values. so you have 2#x = 1 and #x = 1. so x = 1 and (1/#2) .

then find dy/dx, substitute these x values in to find the gradient. then do the usual y=mx + c by putting in the x and y to find c so you then have the eqn's of the two tangents.
then when you've done that, make them equal to each other to find the x value of where they intersect, sub it into one of the tangent eqn's to find y. and you're done.

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