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# OCR Mechanics 1 25th Jan watch

1. for question 4 I get 1.96 and 3.99. Why is this not right? I notice to get 0.49 you can do 1.96/3.99
2. (Original post by Mr M)
Your school has to join. It is not for individuals but it is free.

http://www.furthermaths.org.uk/register.php
What if I'm the only one in my school doing further maths??
3. (Original post by Virgil)
Mr. M would it be possible for you to post solutions to all the questions with the working because I would really like to know the steps for each question?
Despite the overwhelming body of evidence that suggests otherwise, I do have a life Virgil!
4. (Original post by JChoudhry)
What if I'm the only one in my school doing further maths??
5. (Original post by Haruhi)

And also, for the last question I found v when a=0.11 and used that value of v as u when the log was sliding down, I used -3.15 as acceleration. Somehow I ended up with t= 0.48

Do I get any marks for that?
probably 2 or 3
6. (Original post by Mr M)
mr m, for q4, i resolved wrong, therefore my parallel and perendicular components were the other round, and hence, my myu value was x/y as opposed to y/x, (just an example with the x and ys) out of the 6 marks, how many would i lose?
7. (Original post by Mr M)
And it is free for the school as well?
8. (Original post by audiofish)
for question 4 I get 1.96 and 3.99. Why is this not right? I notice to get 0.49 you can do 1.96/3.99
Which part of 4 are you talking about and what did you do to obtain these numbers?
9. (Original post by JChoudhry)
And it is free for the school as well?
Yes.
10. (Original post by purplestarfish)
mr m, for q4, i resolved wrong, therefore my parallel and perendicular components were the other round, and hence, my myu value was x/y as opposed to y/x, (just an example with the x and ys) out of the 6 marks, how many would i lose?
I'm not sure. You might get a couple of marks if you showed your working.
11. does anyone have the paper?
12. (Original post by Mr M)
Which part of 4 are you talking about and what did you do to obtain these numbers?
part one. i got the numbers from 0.4gcos60 and 0.4gsin60 (resolving vertically and horizontally)
13. (Original post by Mr M)
Despite the overwhelming body of evidence that suggests otherwise, I do have a life Virgil!
A simple no would have sufficed mate
14. (Original post by audiofish)
part one. i got the numbers from 0.4gcos60 and 0.4gsin60 (resolving vertically and horizontally)
Ok, you have failed to account for the string attached to the particle P.
15. (Original post by Virgil)
A simple no would have sufficed mate
Why use one word when fifteen will do?
16. (Original post by Mr M)
Why use one word when fifteen will do?
Are you actually kidding?.. you're more dense than the set of irrationals?
17. Waaaaaaay too nerdy
18. OMG what is going wrong with me in these new OCR papers.....did a past paper yesterday and got about 90% then do this paper and according to Mr.M's answers im looking at about 40/72 !?!?!?!?! FML .....worked so hard for these aswell!
19. Mr M, on Q4 I found the T=3.36N and a=1.4 for the pulley. I then used them to find R=0.28 and F=0.49 (apparently wrong). On dividing to find mu, I got 1.75. Was there a quick way to find R and F without having to find T and a?
20. (Original post by Mr M)
I doubt it. I think your memory is letting you down.

Imagine putting an object on a surface and then tilting it until it forms an angle of 60 degrees with the floor. That object and surface would both have to be mighty rough to prevent the object from sliding don't you think?
http://en.wikibooks.org/wiki/A-level..._of_a_Particle Under friction, it has a limit on mu. Dammit.

I think the website is wrong, or worded badly or I didn't read it properly. Either way, I read the article the night before the exam and thought that mu had max value of 1 - spent a good 15mins thinking that I had done something wrong in that q4 when instead I could have have checked my q9...

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