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    Can someone explain how I would do part b in the attachment? I'm going crazy!!! :mad:
    Can some genius please enlighten me! :p:
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  1. File Type: doc 63.doc (119.0 KB, 64 views)
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    Bump!
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    (Original post by Narik)
    Bump!
    Well you know that xy=c^2 then y=c^2/x. Sub that into the normal equation, rearrange and you'll have a quadratic in x which you can hopefully solve.
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    (Original post by ukdragon37)
    Well you know that xy=c^2 then y=c^2/x. Sub that into the normal equation, rearrange and you'll have a quadratic in x which you can hopefully solve.
    Yeah I tried that, but I don't get a bloomin' quadratic!

    (c^2)/x = (t^2)x + (c/t) - ct^3

    Now what!?
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    factorise the x terms

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    tc^{2}=t^{3}x^{2}+x(c-ct^{4})
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    (Original post by Narik)
    Yeah I tried that, but I don't get a bloomin' quadratic!

    (c^2)/x = (t^2)x + (c/t) - ct^3

    Now what!?
    Now multiply both sides by x and do you not have a quadratic in x?
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    (Original post by KeineHeldenMehr)
    factorise the x terms

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    tc^{2}=t^{3}x^{2}+x(c-ct^{4})
    I'm sorry but could you give me the next step! :p:
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    (Original post by Narik)
    I'm sorry but could you give me the next step! :p:
    Move tc^2 to other side and use quadratic formula. (Or complete the square if you prefer)
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    (Original post by ukdragon37)
    Move tc^2 to other side and use quadratic formula. (Or complete the square if you prefer)
    That's like impossibel to solve! :cry2:

    ...for me anyway!



    ooh no wait! i got it! halleluljah!!



    and i must add...


    ****ing s*** was that hard!
 
 
 
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