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# C4 Integration- Players only... watch

1. Can't do this qu. the shape of the curve the frustrating part. Diagram attached.

Diagram shows the curve x = 2t, y=3/t

a. Find areas A and B

for working out A, i plugged in x =1 and x =3 into x = 2t to find two values of t, which i used as limits. I then used the standard formula

A = (curly f) t2 on top, t1 on bottom: y dy/dx dt

but when it came to integrating, it all came out as zero. Where have i gone wrong?

thanks. also rep x
Attached Images

2. Could you write out some workings for us, so we can see where you've gone wrong.
3. Just lol now.
4. the problem is probably that you got the formula wrong. I don't know how to use LaTeX, but it should be:

Int: y (dx/dt) dt with the t values as the limits.

not (dy/dx)
5. Can you not just change from parametric by eliminating t, to get equation in usual format? i.e. get:

Must admit bit rusty on parametrics so this could be a no no - please let me know if so!

EDIT

Checked with this formula
Int: y (dx/dt) dt with the t values as the limits.
Result is the same

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