Can't do this qu. the shape of the curve the frustrating part. Diagram attached.
Diagram shows the curve x = 2t, y=3/t
a. Find areas A and B
for working out A, i plugged in x =1 and x =3 into x = 2t to find two values of t, which i used as limits. I then used the standard formula
A = (curly f) t2 on top, t1 on bottom: y dy/dx dt
but when it came to integrating, it all came out as zero. Where have i gone wrong?
thanks. also rep x
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- Thread Starter
- 25-01-2010 21:41
- 25-01-2010 21:47
Could you write out some workings for us, so we can see where you've gone wrong.
- 25-01-2010 21:49
Just lol now.Last edited by Clarity Incognito; 25-01-2010 at 22:03.
- 25-01-2010 21:57
the problem is probably that you got the formula wrong. I don't know how to use LaTeX, but it should be:
Int: y (dx/dt) dt with the t values as the limits.
Last edited by spread_logic_not_hate; 25-01-2010 at 22:41.
- 25-01-2010 22:37