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    Hey,


    I had a quick question:

    What are the reaction conditions for the nucleophilic substitution and elimination reactions between NaOH and a haloalkane... the textbook and internet contradict the mark schemes

    Here is what i think they are:
    Nu Subst: aq/alc NaOH.. warm reflux...
    Elim: alc conc. NaOH... hot reflux...

    The MS penalises for saying reflux and conc.. can anyone explain which one is correct?

    Also can anyone tell me the reaction conditions for the industrial production of aspirin... i thought they were 90 degrees celsius with ethanoic anhydride... is this correct?

    thanks in advance
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    i was taught substitution: cold OH- in water, elimination: hot OH- in ethanol
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    subsitution would be: weak, NaOH (aq), reflux - product alcohol
    Elim would be: Conc NaOH in alcohol, reflux - product alcene
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    (Original post by blonde-beth)
    i was taught substitution: cold OH- in water, elimination: hot OH- in ethanol

    oh... but the MS even contradicts that.. and you would need alcohol present in substitution as well in order for the haloalkane to dissolve... no?:confused:
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    (Original post by AdotK)
    oh... but the MS even contradicts that.. and you would need alcohol present in substitution as well in order for the haloalkane to dissolve... no?:confused:
    well its what my AS chem text book of last year tells me :p: if your looking for whats right go with the mark scheme.
 
 
 
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