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differentiating sinxcos(-y) watch

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    Hi

    I'm working on the implicit question sinxcos(-y)=tanxy which I have to get dy/dx from. I've just managed to differentiate tanxy, and I have nearly done the first bit, differentiating sinxcos(-y) but do I leave it in this form or do I simplify further?

    sinxcos(-y)= -cosxcos(-y)/sinxsin(-y)
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    (Original post by hamzramz)
    Hi

    I'm working on the implicit question sinxcos(-y)=tanxy which I have to get dy/dx from. I've just managed to differentiate tanxy, and I have nearly done the first bit, differentiating sinxcos(-y) but do I leave it in this form or do I simplify further?

    sinxcos(-y)= -cosxcos(-y)/sinxsin(-y)
    cos(-y)=cosy
    cos is an even function
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    (Original post by hamzramz)
    Hi

    I'm working on the implicit question sinxcos(-y)=tanxy which I have to get dy/dx from. I've just managed to differentiate tanxy, and I have nearly done the first bit, differentiating sinxcos(-y) but do I leave it in this form or do I simplify further?

    sinxcos(-y)= -cosxcos(-y)/sinxsin(-y)
    So the equation is sin x cos y = tan xy
    Differentiate sin x cos y using the product rule.
    Differentiate tan xy using the chain rule.
    Collect like terms.
 
 
 
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