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# Quick Chemistry question about Kc watch

1. Hi,

can somebody plzz help me with this q

C2F4 is obtained from CHClF2 according to the equation:

2(CHClF2) <===> C2F4 + 2(HCL)

a 1.0 mol sample of CHCLF2 is placed in a container of volume 18.5dm3 and heated.
When the equilibrium is reached, the mixture contains 0.20 mol of CHClF2

i)Calculate the number of moles of C2F4 & no of moles of HCL at equilibrium

I know that HCL=0.8 and and C2F4 is 0.4 because i checked the mark scheme...but i have absolutely no clue how C2F4 = 0.4...in my answer i put 0.9 thinking it was that.

Help?
2. Just consider the molar ratios
3. (Original post by Circularmover)
Hi,

can somebody plzz help me with this q

C2F4 is obtained from CHClF2 according to the equation:

2(CHClF2) <===> C2F4 + 2(HCL)

a 1.0 mol sample of CHCLF2 is placed in a container of volume 18.5dm3 and heated.
When the equilibrium is reached, the mixture contains 0.20 mol of CHClF2

i)Calculate the number of moles of C2F4 & no of moles of HCL at equilibrium

0.20 mol of CHClF2 at eqm means that 0.80 mol has reacted to form products. Therefore mol of C2F4 = 1/2 mol of CHClF2 reacted = 0.40 mol

mol of HCL at eqm = mol of CHCLF2 reacted = 0.80 mol

I know that HCL=0.8 and and C2F4 is 0.4 because i checked the mark scheme...but i have absolutely no clue how C2F4 = 0.4...in my answer i put 0.9 thinking it was that.

Help?
Hope that helps.

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