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    can someone help me with this maths question ;
    f(x) = (2x-1)^5 - find the stationery point
    Im struggling to multiple the bracket out

    its from 2006 pastpaper and worth 7 marks!!
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    There's no need to multiply the brackets out. All you need to do is find \frac{df(x)}{dx} and equate that to 0.
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    Differentiate f(x).
    Let's say:
    y = (2x - 1)^5
    then:
    \frac{dy}{dx} = 5.(2x-1)^{4} . 2 = 10(2x-1)^{4}
    And the stationary point is when \frac{dy}{dx} = 0
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    yup tgodkin is right
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    (Original post by Wednesday Bass)
    Differentiate f(x).
    Let's say:
    y = (2x - 1)^5
    then:
    \frac{dy}{dx} = 5.(2x-1)^{4} . 2 = 10(2x-1)^{4}
    And the stationary point is when \frac{dy}{dx} = 0
    thankyou thankyou I found the question in a pastpaper and we have yet to cover it in class so thanks
 
 
 
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Updated: January 26, 2010
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