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    A 3kg mass is on a smooth slope inclined at 30 degrees to the horizontal. What horizontal force needs to be applied to keep the body in place? I get 16.97 N but my friend gets 12.73. :confused: Please help! :woo:
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    I get 16.97
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    (Original post by 2710)
    I get 16.97
    Cool thanks! Anyone else?
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    Wouldn't it be better to ask to show your friends working?
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    (Original post by 2710)
    Wouldn't it be better to ask to show your friends working?
    Yeah... we have tried to discuss it. :rolleyes:
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    (Original post by innerhollow)
    Well, let's see. A 3kg mass has weight of 3*9.8, which is 29.4N

    This would mean that to stop it, you'd need a force equal to the component of the weight acting down the slope, which would be 29.4*sin30, which is 14.7N

    ... What the hell?! Um, how did both of you get 16.97N? :confused:
    You are applying a horizontal force. Not a force perpendicular to the slope
 
 
 
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