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    Hey people!
    I'm studying maths at uni and someone just asked me to find the limit of the following function as x tends to 0.
    y=(1-2(sin^2)x-(cos^3)x)/5x^2
    My first thought was that it had an asymptote at x=0 since the function has a 5x^2 at the bottom and as x tends to 0 the function goes off to infinity. However apparently the limit is -0.1. I've graphed it on wolframalpha.com and it does indeed cross the y-axis at -0.1. Am i just missing something really trivial or what? Help please
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    Look up L'Hopitals rule.

    Basically you look at the differentials of the top and bottom, if otherwise you would have 0/0
 
 
 
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Updated: January 26, 2010

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