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POST-EXAM CHAT: OCR Chemistry- Rings, Polymers and Analysis - F324 thread watch

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    (Original post by sa121)
    LOL!! aaahhh no worries...u still may get the mark? At least u didnt put absorption
    Haha, I was contemplating as to whether or not I should make my writing suddenly even more obscure so it's hard to identify if it's a b or a p.
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    (Original post by Summerdays)
    Which bit are you refering to? For the NMR I got an ester, but the wrong ester because I didn't realise there were seven peaks (and not four).
    i quoted you about the impurity.
    what structure did you draw for it?
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    (Original post by _lynx_)
    But it was on a benzene ring, so I'm not sure if that would work out...

    I wrote the same thing as you btw.
    What do toher people think?
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    (Original post by sa121)
    It wasn't a ketone it was an ester no? It was attached to an Oxygen as well.
    if i remember, the question asked "name the functional groups present in both Paracetomal and the other one.." so surely there was a Ketone present in one of them having a C=O in the middle of the compound! And yes, there was an ester too!
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    (Original post by Noble.)
    No, it doesn't work. You would end up with carbon having five bonds, which doesn't work.
    no you wouldnt, becaue the carbon will be connect to a carbon either side and also connected to an oxygen by a double bond, so thats four bonds.
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    (Original post by The_wise)
    For the last question, part C: the alcohol was a secondary alcohol right? so when u add acidified dichromate you get a ketone?

    Agree anyone? x
    haha, i remember trying this myself :p:
    no. as it is a benzene ring, if a ketone formed from one of teh carbons,
    it would effectively have 5 bonds C-C, C=O, C-C, and the delocalised e- bonding.
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    (Original post by The_wise)
    no you wouldnt, becaue the carbon will be connect to a carbon either side and also connected to an oxygen by a double bond, so thats four bonds.
    I think you're forgetting about the fact it was a benzene ring.
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    (Original post by The_wise)
    no you wouldnt, becaue the carbon will be connect to a carbon either side and also connected to an oxygen by a double bond, so thats four bonds.
    +benzene ring = 5
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    Hi
    I need edexcel As chemistry by Ann fullick
    ISBN 9781405896351
    I need this book as i dont want to buy a new one.

    IF any one has it in good condition i an ready to buy it in low price
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    (Original post by Pedus)
    if i remember, the question asked "name the functional groups present in both Paracetomal and the other one.." so surely there was a Ketone present in one of them having a C=O in the middle of the compound! And yes, there was an ester too!
    if the C=O was next to C-O then it is only an ester not ketone aswel
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    (Original post by ashu12345678)
    Hi
    I need edexcel As chemistry by Ann fullick
    ISBN 9781405896351
    I need this book as i dont want to buy a new one.
    IF any one has it in good condition i an ready to buy it in low price
    OCR thread :rolleyes:
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    And I'll ask again since nobody is responding:
    On the last question:
    Halogenalkane with peptide bond in one of them (can't remember whether aspirin or paracetamol), would it work to form a tertiary amine??
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    (Original post by andy892)
    And I'll ask again since nobody is responding:
    On the last question:
    Halogenalkane with peptide bond in one of them (can't remember whether aspirin or paracetamol), would it work to form a tertiary amine??
    I'm not sure I know what you mean.
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    (Original post by Noble.)
    I'm not sure I know what you mean.
    In paracetamol (I've now worked this out), there is a peptide bond.
    Is it possible that this could react with a halogenoalkane because the lone pair on the nitrogen atom would attack the electron defficient carbon in the C-X bond?
    Therefore, this would be a reagent used that would only react with paracetamol, as the same cannot be said for aspirin..
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    (Original post by Noble.)
    No, it doesn't work. You would end up with carbon having five bonds, which doesn't work.
    I wrote add bromine as the other molecule wont react with bromine without a halogen carrier catalyst
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    How many C13 peaks did everyone get?
    I think it was for carboxylic acids. And i think the two we had to compare were pentanoic acid and 2,2-dimethylpropanoic acid?
    Therefore, pentanoic acid has 5 C environments and the other ones has 3??
    That's if it was those carboxylic acids we had to compare..
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    would febr3 work for both? and what would happen to the benzene with the phenol... still just c6h5BR, not 3, as there is just 1 BR from the BR+?
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    That question about the difference in reactivity with bromine between Phenol, Bromine and Cyclohexene...

    Only worth 5 marks? I could write an essay about that stuff!
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    still no unoffical marksheme
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    Has anyone got the paper?
 
 
 
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