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    heyy,
    i know this log is really simple but just started them, so i dont no how to go further to solve it, please could someone explain!

    9 ^ (x+5) = 50
    so i did:
    (x+5) log 9 = 50
    x log 9 + 5 log 9
    x log 9 + log9^5 = 50

    i dont no where to go from there, ive tried all sorts but still dont seem to able to get the right answer

    thankyou in advance
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    You're perfect up to (x+5) log 9 = 50, but you've done some not incorrect, but unnecessary, steps. Divide both sides to get: x + 5 = 50 / log 9; now can you see how to finish it off?
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    ohh yeah, i see... ive managed to get -3.22 finally .. thankyou
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    just do log(base)9- 50=x+5

    then take the 5 over
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    (Original post by _anum)
    heyy,
    i know this log is really simple but just started them, so i dont no how to go further to solve it, please could someone explain!

    9 ^ (x+5) = 50
    so i did:
    (x+5) log 9 = 50
    x log 9 + 5 log 9
    x log 9 + log9^5 = 50

    i dont no where to go from there, ive tried all sorts but still dont seem to able to get the right answer

    thankyou in advance
    You should have taken logs of both sides.
    (x+5)\log{9}=\log{50}
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    okayy .... thankyou all
 
 
 
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