#1

mass of block = 1 kg
voltage = 12
current= 4.07
initial temp=23
final temp =38
time taken = 6 min

what is the energy given to the aluminium block and from that work out the specific heat capacity.
and give any physical reasons for any discrepancy between this result and the published one.
0
8 years ago
#2
P=IV and E=Pt. We can also express energy as q = mcΔT. Can you see how to combine & rearrange these to find the specific heat capacity, c?

As for the second part, think about how the real-life conditions might differ from the idealized ones in your calculation. (In particular, think about the temperature.)
0
#3
(Original post by YHF)
P=IV and E=Pt. We can also express energy as q = mcΔT. Can you see how to combine & rearrange these to find the specific heat capacity, c?

As for the second part, think about how the real-life conditions might differ from the idealized ones in your calculation. (In particular, think about the temperature.)

yeah thank you
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