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# c2 logarithm help watch

1. How do i solve these equations... Can i have a step by step answer as i missed it in class

1. 2(3^2x) - 7(3^x) + 6 =0
2. log base 4x - 3log base x4= 2
2. 1.Note that , so your equation reduces to 2u^2 - 7u + 6 = 0 where u = 3^x.

2. Do you know the base changing formula? (If not, search for it; I've forgotten it.)
3. (Original post by ghostkillah)
log base 4x - 3log base x4= 2

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