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# general solution watch

1. Hi
Can someone kindly get me on to the right track, i am kinda lost maybe because i am doing it late lol. Anyways, the questions are: find general solution of 2cos^2x=1 .4sin^2 (2x)=3
for the first one i thought of using the trig . identity but grr i keep getting wrong values.
Thanks .
2. LOL another question, this ones bothering me real bad.
solve: 1+sin(3x+1) = 0.3
Well i started off by timing out the brackets:
1+sin3x+sin= 0.3
sin3x+sin = 0.3-1
sin3x= sin^-1 (-0.7)
sin3x = about -0.77539
3x= sin^-1 (-0.77539)
x= -0.8873/ 3 = which gives me -0.25 -.-
3. (Original post by ibysaiyan)
LOL another question, this ones bothering me real bad.
solve: 1+sin(3x+1) = 0.3
Well i started off by timing out the brackets:
1+sin3x+sin= 0.3
sin3x+sin = 0.3-1
sin3x= sin^-1 (-0.7)
sin3x = about -0.77539
3x= sin^-1 (-0.77539)
x= -0.8873/ 3 = which gives me -0.25 -.-
You can't 'multiply out' the bracket.
4. (Original post by gilbo)
You can't 'multiply out' the bracket.
Oh.. great now what, do i send it to the left or let x= -1/3?> hmm

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