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    Can anyone help me with this question:
    Show that:
    (\tan \theta+\cot \theta)(\sin \theta+\cos \theta)\equiv \sec \theta+\mathrm{cosec} \theta
    Thanks
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    Can anyone help me with this question:
    Show that:
    (\tan \theta+\cot \theta)(\sin \theta+\cos \theta)\equiv \sec \theta+\mathrm{cosec} \theta
    Thanks
    Consider that

     tan \theta + cot \theta = tan \theta + \frac{1}{tan \theta} = \frac{tan^2 \theta + 1}{tan \theta}

    and the identities

     sec^2 \theta = 1 + tan^2 \theta

    and

     tan \theta = \frac{sin \theta}{cos \theta}

    This should get you on the way to the answer!
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    still don't get it. sorry.
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    thats simple..all you have to do is change tan and cot to sin and cos (tan=sin/cos and cot=cos/sin)take common denominator and should get sin^2+cos^2 which is 1 and then you should be able to work yourself out
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    (Original post by saran35)
    still don't get it. sorry.
    Post your working/explain exactly where you get stuck then. We're not going to do your homework for you.
 
 
 
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