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    • Thread Starter

    how would I work out y=sin^2x/cos^3x
    I tried the quoitent rule, using u=sin^2x and v=cos^x, but that didn't work.
    Then I thought it was equal to tan^2x/cosx, and tried to differentiate that, but it also did not work.

    • Community Assistant
    • Study Helper

    Community Assistant
    Study Helper
    You've titled this as an integration problem, then you've written: 'how would I work out y=sin^2x/cos^3x' which doesn't mean anything and then your working implies differentiation:confused: :confused: :confused:

    If it is differentiation and you've tried the quotient rule, post your working up to the point you get stuck.

    In future, you should always make everything clear in your post or you may not get any replies.

    You've simplified it correctly.

    Can you integrate tan^2x easily? No.
    Can you differentiate it easily? Yes.
    let u = tan^2x, v = sexc (1/cosx)

    I think anyway.
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