how would I work out y=sin^2x/cos^3x
I tried the quoitent rule, using u=sin^2x and v=cos^x, but that didn't work.
Then I thought it was equal to tan^2x/cosx, and tried to differentiate that, but it also did not work.
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Last edited by Lola4000; 01-02-2010 at 17:16.
- 01-02-2010 17:03
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- 01-02-2010 17:35
You've titled this as an integration problem, then you've written: 'how would I work out y=sin^2x/cos^3x' which doesn't mean anything and then your working implies differentiation
If it is differentiation and you've tried the quotient rule, post your working up to the point you get stuck.
In future, you should always make everything clear in your post or you may not get any replies.
- 01-02-2010 18:19
You've simplified it correctly.
Can you integrate tan^2x easily? No.
Can you differentiate it easily? Yes.
let u = tan^2x, v = sexc (1/cosx)
I think anyway.