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# fp2 - integrating inverse trig (another question!) watch

1. Hi,

Given that: - inverse sin(x)

show that x (inverse sin(x)) / sqrt(1-x^2)

I differentiated using product rule but ended up with

dy/dx = - inverse sin(x) / (2 sqrt(1-x^2))

(Sorry about the lack of LaTeX, I'm having major issues with it).
Any help would be appreciated
2. To clarify:

To be shown:

right?
3. (Original post by zdo0o)
To clarify:

To be shown:

right?

Nearly, except in the y = ... it should be sqrt (1-x^2) multiplied by arc sin...
4. Product rule gives:

dy/dx = 1 - [x(1-x^2)^-0.5 x arcsinx + (1-x^2)^0.5 x 1/sqrt(1-x^2)]

See if you can go from there.
5. Done, thank you. I forgot about the fact that the bracket was quadratic when I used the product rule.

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Updated: February 1, 2010
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