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    Is it Effort/Load or Load/effort?

    And what's the displacement ratio?
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    It's Load/Effort (both are forces)
    The bigger the load you can move with a smaller effort, the bigger your mechanical advantage. (Mechanical advantage is sometimes called force ratio.)
    Displacement ratio is the same as velocity ratio.
    It measures the ratio of the distance you move the effort divided by the distance you move the load (in the same time).
    In an ideal simple machine, with no loss due to friction, mechanical advantage = velocity ratio.
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    (Original post by Lehane)
    Is it Effort/Load or Load/effort?

    And what's the displacement ratio?
    Sometimes it can be really useful for physics questions such as these to see how the equation varies with changing values.

    If you were to increase effort, and the mechanical advantage was to go up.. That wouldn't make much sense. For MA = effort/load, isnt this exactly what would happen?

    Thus load/effort has to be the answer
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    Thanks guys My brain had a meltdown yesterday but I understand now
 
 
 
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