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    I'm having trouble working out this question:

    The equilibrium constant for the reaction

    2NO2(g) ⇌ 2NO(g) + O2(g)

    is 9 moldm-3 at 683K

    equilibrium concentrations were measured as
    NO(g) = 0.5 moldm-3
    O2(g) = 0.25 moldm-3

    What is the equilibrium concentration of NO2(g) in the above mixture.

    I know the answer is 0.083 but I can't get to it.


    Okay so:

    K_c = \frac{[NO]^2[O_2]}{[NO_2]^2}

    and 9 = [0.5]2[0.25]/[NO2]2

    so rearrange so that [NO2]2 = [0.5]2[0.25]/9

    then take the square root :yep:
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