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Equilibrium constant calculation help.

I'm having trouble working out this question:


The equilibrium constant for the reaction

2NO2(g) ⇌ 2NO(g) + O2(g)

is 9 moldm-3 at 683K

equilibrium concentrations were measured as
NO(g) = 0.5 moldm-3
O2(g) = 0.25 moldm-3

What is the equilibrium concentration of NO2(g) in the above mixture.

I know the answer is 0.083 but I can't get to it.

+REP
Okay so:

Kc=[NO]2[O2][NO2]2K_c = \frac{[NO]^2[O_2]}{[NO_2]^2}

and 9 = [0.5]2[0.25]/[NO2]2

so rearrange so that [NO2]2 = [0.5]2[0.25]/9

then take the square root :yep:

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