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# SUVAT - help! watch

1. i get so confused here....

hre's the question, can some brain box explain why/how to do it?

A bullet, fired vertically from a pistol, rises to a maximum height of
1875 m above a planet in a time of 25 seconds.
(i) Calculate the average speed of the bullet during this time.
Average speed = _____________ m/s [4]
(ii) Using your answer to part (i), or otherwise, calculate the maximum
speed of the bullet.
Maximum speed = _____________ m/s [3]
2. (i) = 1875/25 = 75
(ii) = squar root of 2*9.8*1875
(i) = 1875/25 = 75
(ii) = squar root of 2*9.8*1875
Don't just post the answers. The idea is to explain it as so they can understand it
4. For question i) i would assume you also need to take into account from the direction of the velocity of the bullet the acceleration is
-9.8ms^-2 due to gravity.
5. figured it out and i'm glad. the method for these questions is to wrtie:
S
U
V
A
T

which of thse do we know?

S=1875
U=0
V=X(this is the question)
A=unknown as bullet is fired above A PLANET, NOT EARTH SO A ISN'T known and is useless
T=25s

SUVT

a) average speed=total distance/total time=1875/25= I dunno lol cba to calculate
b)find V in other words.

S=1/2(U+V)T

(S/0.5)X25=V
V= summit

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Updated: February 7, 2010
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