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# FP2 Maclaurin Series watch

1. Using the series expansion for ln(x+1), find correct to 3dp the value of ln(6/5)

I don't understand the first step, how to find x? I get what you do after that but how do you get x=0.2
2. Well, if you want ln(6/5), and you know how to find ln(x+1), it would seem logical to try x+1 = 6/5.
3. (Original post by DFranklin)
Well, if you want ln(6/5), and you know how to find ln(x+1), it would seem logical to try x+1 = 6/5.
Thank you!

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