The Student Room Group
Reply 1
You're given the formula in the exam, you should learn how to use it without nCr as you can't use it in the C4. Anyway, the formula is:

(a+b)^n = a^n + (a^n)(b) + n(n-1)/2! x a^n-2 x b^2 +n(n-1)(n-2)/3! x a^n-3 x b^3......
Reply 2
no i just need a way of working out the 4 nCr 2 bit.. i can do the rest of the expansion.
Reply 3
cuddles x
no i just need a way of working out the 4 nCr 2 bit.. i can do the rest of the expansion.

(nr)=nCr=n!r!(nr)!\displaystyle \binom{n}{r} = {^n}\mathrm{C}_r = \frac{n!}{r!(n-r)!} :smile:

EDIT: Only for integer values of n & r, of course. :yep:
Reply 4
james.h
(nr)=nCr=n!r!(nr)!\displaystyle \binom{n}{r} = {^n}\mathrm{C}_r = \frac{n!}{r!(n-r)!} :smile:



wicked thanks.:woo:

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