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    Where've i gone wrong??
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    (Original post by FoOtYdUdE)
    Where've i gone wrong??
    well show your working
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    (Original post by FoOtYdUdE)
    I get


    This is correct. Wolfram has just simplified it a bit.

    Try taking (x+1)^(3/2) out as a factor and re-arrange.
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    u=x
    du/dx= 1
    dv/dx= (x+1)^1/2
    v= 2/3 (x+1)^2/3


    then u do:

    UV - INTEGRAL V(du/dx)dx


    right? so why do i get the wrong answer? :o:
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    (Original post by ghostwalker)
    This is correct. Wolfram has just simplified it a bit.

    Try taking (x+1)^(3/2) out as a factor and re-arrange.
    ermmmmm:o:
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    (Original post by FoOtYdUdE)
    ermmmmm:o:
    Is that an ermmmm of confusion? Or did that make sense?
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    (Original post by ghostwalker)
    Is that an ermmmm of confusion? Or did that make sense?
    still doesn't make sense, i'm sorry.

    i'm using

    uv - integral v (du/dx) dx

    that formula....argh, i'm gertting annoyed.
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    thanks for persevering with me guys,
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    \displaystyle\frac{2}{3}x(x+1)^{  3/2}-\frac{4}{15}(x+1)^{5/2}

    \displaystyle=(x+1)^{3/2}\left[\frac{2}{3}x-\frac{4}{15}(x+1)\right]

    \displaystyle=\frac{1}{15}(x+1)^  {3/2}\left[10x-4(x+1)\right]

    \displaystyle=\frac{1}{15}(x+1)^  {3/2}\left[6x-4\right]

    \displaystyle=\frac{2}{15}(x+1)^  {3/2}(3x-2)
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    (Original post by ghostwalker)
    \displaystyle\frac{2}{3}x(x+1)^{  3/2}-\frac{4}{15}(x+1)^{5/2}

    \displaystyle=(x+1)^{3/2}\left[\frac{2}{3}x-\frac{4}{15}(x+1)\right]

    \displaystyle=\frac{1}{15}(x+1)^  {3/2}\left[10x-4(x+1)\right]

    \displaystyle=\frac{1}{15}(x+1)^  {3/2}\left[6x-4\right]

    \displaystyle=\frac{2}{15}(x+1)^  {3/2}(3x-2)
    Amazing!!!!!!!!!!!!!
 
 
 
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