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some partial fractions and binomial expansions questions.. watch

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    The question is
    express 3(x+1)
    (x+2)(x-1)
    x ER x isnt -2, x isnt 1 )the equals with a dash through!)
    so i gotL
    1/(x+2) + 2/(x-1)
    Part b says hence or otherwise prove that f'(x)<0 for all values of x in the domain. ...what do i do here? I know i differentiate but the what?
    ------
    Find the first 3 terms in the expansion
    (x+4)
    (1+3x)^2

    so i expanded (1+3x)^2 but now have:
    (x+4)(1-6x+27x^2-108x^3)
    what do i do? multiply them together?
    Thanks
    xxx
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    (Original post by indie_couture)
    The question is
    express 3(x+1)
    (x+2)(x-1)
    x ER x isnt -2, x isnt 1 )the equals with a dash through!)
    so i gotL
    1/(x+2) + 2/(x-1)
    Part b says hence or otherwise prove that f'(x)<0 for all values of x in the domain. ...what do i do here? I know i differentiate but the what?
    ------
    Find the first 3 terms in the expansion
    (x+4)
    (1+3x)^2

    so i expanded (1+3x)^2 but now have:
    (x+4)(1-6x+27x^2-108x^3)
    what do i do? multiply them together?
    Thanks
    xxx
    I suggest you try and use latex.

    You should not have expanded (1+3x)^2 what you should have expanded was (1+3x)^{-2} and then multiply by (x+4)
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    (Original post by steve2005)
    I suggest you try and use latex.

    You should not have expanded what you should have expanded was and then multiply by
    i meant i did expand that, so i just multiply, yes? xxx
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    (Original post by indie_couture)
    i meant i did expand that, so i just multiply, yes? xxx
    Yes
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    i am sorry but i don't really don't understand what you're saying in your question OP
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    (Original post by indie_couture)
    The question is
    express 3(x+1)
    (x+2)(x-1)
    x ER x isnt -2, x isnt 1 )the equals with a dash through!)
    so i gotL
    1/(x+2) + 2/(x-1)
    Part b says hence or otherwise prove that f'(x)<0 for all values of x in the domain. ...what do i do here? I know i differentiate but the what?
    ------
    Find the first 3 terms in the expansion
    (x+4)
    (1+3x)^2

    so i expanded (1+3x)^2 but now have:
    (x+4)(1-6x+27x^2-108x^3)
    what do i do? multiply them together?
    Thanks
    xxx
    Hey where is this question from? and yes that is what you would do
 
 
 
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