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    I'm not sure what equation to use, I keep getting the wrong answer can someone please help me out here?

    Question: A spanner was dropped from a hot air balloon when the balloon was at rest 50m above the ground. Calculate the time taken for the spanner to hit the ground
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    s=50
    a=9.81
    u=0

    use s=ut+(at^2)/2

    50 = 4.9t^2

    t = sqrt(50/4.9)
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    Thanks one more question:
    As astrounaut on the Moon threw an object of 4.0m vertically upwards and caught it again at 4.5s later. Calculate te acceleration due to gravity on the Moon
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    s=2
    t=2.25
    v=0

    s=(u+v)t/2

    then v=u+at
 
 
 
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