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# The 2010, Honorary Member Welcoming, Undergraduate Degree Results Chat Thread Mk. V watch

1. I can so stats, I just find it stupid.
2. (Original post by maxfire)
use

den look up z in a forumla table na meen.

Can you talk me through this, I'm a tard at remembering this.

What do I replace n and xbar with?

I forgot it all
3. (Original post by + polarity -)
I was waiting for it too.

Smelly Ali.
Weren't you meant to give me an amazing rep you'd written me on or near Valentines day I seem to remember
4. xbar
5. (Original post by Crazy Paving)
xbar

there is nothing sexy about stats.
6. (Original post by aliluvschoc)
uhm I'm not sure.

I'll type the question hang on. It's easy, I've done this before a million times but it all suddenly looks like a foreign language.

IQ test scores; in a normal distribution with mean=100, standard deviation=20

I need to find the probability that a random individual will score more than 108
One sec I'll rummage for my stats book. ND is a ***** though. I say to start, draw a diagram of the distrubution and shade the area you need i.e everything above 108, 100 will be the middle of the ditrubution.

You need to find Z, in which you do

Then the probability will be:
P(Z>1.08) = 1-(psi)1.08
=1-0.8559
=0.1441

[I think, someone correct me if incorrect]
7. (Original post by aliluvschoc)
Weren't you meant to give me an amazing rep you'd written me on or near Valentines day I seem to remember
I was banned at the time.

I commented on the wall of this group (scroll a bit). The reaction was expected.
8. (Original post by aliluvschoc)

there is nothing sexy about stats.
I know. Sounds like chocolate bar.

What about those statisticians who wear white lab coats and gloves?
9. And who the **** is this guy?
10. lolarity
11. (Original post by Loz17)
One sec I'll rummage for my stats book. ND is a ***** though. I say to start, draw a diagram of the distrubution and shade the area you need i.e everything above 108, 100 will be the middle of the ditrubution.

You need to find Z, in which you do

Then the probability will be:
P(Z>1.08) = 1-(psi)1.08
=1-0.8559

[I think, someone correct me if incorrect]

I got z= (65-108)÷20 =2.15

but I didn't understand the rest of what you put.
12. That's me. Why?
13. (Original post by + polarity -)
I was banned at the time.

I commented on the wall of this group (scroll a bit). The reaction was expected.
I don't have you on facebook, what did you say?
14. alloz
15. aliluvsloz
16. (Original post by Crazy Paving)
I know. Sounds like chocolate bar.

What about those statisticians who wear white lab coats and gloves?
Wait, they really exist?

17. (Original post by Crazy Paving)
aliluvsloz
Shhh, everyone will want some.
18. (Original post by aliluvschoc)
I don't have you on facebook, what did you say?
19. I lol'd at the post above mine, though.
20. (Original post by aliluvschoc)
Can you talk me through this, I'm a tard at remembering this.

What do I replace n and xbar with?

I forgot it all
Hokay, this isn't for definite, but I'm quite sure...

x bar would normally be the sample mean, which is 108, and n is the sample size, which is 1 in this example, as you're only picking one thing. mu is the population mean.

Okay, so

So you look up z = 0.4 in your tables.

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