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    :confused: can any one help me to solve..

    Prove cosec x + cot x = 1/ (cosec x - cot x)



    prove (sec x -1 )/ (tan x) = (tan x) / (sec x + 1)
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    Start from one side and make your way to the other.

    So how can you write? 1/ (cosec x - cot x) in terms of cos and sin? for example?
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    divide both sides of the first equation by cosxcosecx then multiply up and rearrange.
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    (Original post by kexy)
    Start from one side and make your way to the other.

    So how can you write? 1/ (cosec x - cot x) in terms of cos and sin? for example?

    1 / sin x + cos x / sin x
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    (Original post by Totally Tom)
    divide both sides of the first equation by cosxcosecx then multiply up and rearrange.

    how can i divide both side? this is proving q.. means i need to work from one side...
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    oh my.............................. ...........................
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    First one: Multiply the numerator and denominator by (cosec x + cot x) on the RHS (some others have suggested a different way, this is how I would tackle it though)

    Second one: Multiply across the denominators of the fractions and see whether you come across a known identity.
 
 
 
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Updated: February 8, 2010
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