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Mechanics 3 - Review Exercise 1 Q37 watch

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    I have just come across this pickle of a question, the likes of which I have not down before !__! ....I gave it a shot, but I am not sure as to how to take the horizontal component of the string when it is extended into account, so I get the wrong value of extension, moley....anywhoo..


    37) A light elastic string of natural length 5m and modulus 4N has one end fixed to a point O on level ground. To the other end of the string is attached a ball of mass 0.5kg, which is projected vertically upwards from O with speed um/s

    (a) Find u, given that the ball first comes to instantaneous rest when it reaches a height of 10m above the ground.

    ah smudge it, what the hell am I doing, the question doesn't say that the string is flat along the ground...is projected from O.

    I am leaving this here, as I now want to know how the question would be answered if the ball was indeed projected 5 metres from O with the string flat...how would I go about answering the question?

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    If the particle was projected like that, then it would be under the effect of a "central force" due to the tension in the string. This force will act at the particle in a direction towards O. However, here you'd also need to take weight into account which makes the problem considerably harder.
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    PM widowmaker he's the mechanics king
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    (Original post by goku999)
    PM widowmaker he's the mechanics king
    lol, I sent him a pm. He understands it though.
 
 
 
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Updated: July 30, 2005

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