3 + 2log (base 2)x = log (base 2)(10x -3)
i'm confused of what it is when u multiply outside of the brackets
and alos do not know how to change the base to 10 so can go in calculator.
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- Thread Starter
- 07-02-2010 21:11
- 07-02-2010 21:41
Don't forget your logarithmic properties. For example, in the question you posted, 2 log (base 2) x = log (base 2) x^2 from the power property. And from the division property: log (base 2) (10x-3) - log (base 2) x^2 = log (base 2) [(10x-3)/x^2].
So now you have 3 = log (base 2) [(10x-3)/x^2].
And to get rid of the log (base 2) you have to do: 2^3 = 2^ (log (base 2) [(10x-3)/x^2]).
And now you're left with 8=(10x-3)/x^2 and you can just solve for x from there.
Hope it helps.
And to change the base: it's log(everything else)/log(base). For your question base is 2.Last edited by teily; 07-02-2010 at 21:43.