A belt ABCDEFA of length L passes round two wheels, centres O_1 and O_2. The parts ABC and DEF of the belts are in contact with the wheels and parts AF and CD are straight. If O_1A = a and O_2F = 3a and the angle AO_1B = theta radians show that
4atan (theta) = 4a(theta) + L - 6a*pi
Next find the shortest length belt in terms of a.
Im pretty stuck on this one. Any ideas??
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Pure trignometry problem - please help watch
- Thread Starter
- 08-02-2010 13:04
- Study Helper
- 08-02-2010 13:10
As it stands B and E can be any where on the part of the belt touching the corresponding circles. Need more input!