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    A belt ABCDEFA of length L passes round two wheels, centres O_1 and O_2. The parts ABC and DEF of the belts are in contact with the wheels and parts AF and CD are straight. If O_1A = a and O_2F = 3a and the angle AO_1B = theta radians show that

    4atan (theta) = 4a(theta) + L - 6a*pi

    Next find the shortest length belt in terms of a.

    Im pretty stuck on this one. Any ideas??
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    As it stands B and E can be any where on the part of the belt touching the corresponding circles. Need more input!
 
 
 
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Updated: February 8, 2010
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