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    I've tried all the equations and none of them seem to give me the correct answer.

    Here's the question:
    A stone is thrown verically upwards from a point which 3m above the ground, with speed 16ms-1. Find a)the time of flight of the stone b)the total distance travelled by the stone.

    Any help?
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    (Original post by Mist786)
    I've tried all the equations and none of them seem to give me the correct answer.

    Here's the question:
    A stone is thrown verically upwards from a point which 3m above the ground, with speed 16ms-1. Find a)the time of flight of the stone b)the total distance travelled by the stone.

    Any help?
    (a) Use the equation
     V=u+at

    wherein V=0ms^-1, U=16ms^-1 and A=-9.81ms^-1

    thus, solve for t, and then multiply by two(as the time taken for the ball to travel upwards is equal to the time it takes the ball to travel downwards)


    (b)
    Use the equation

    V^2 = U^2 +2AS

    V=0ms^-1, U=16ms^-1 and A=-9.81ms^-1

    Thus, solve for S - which is the distance from the original position to the point wherein the velocity of the ball is zero. Multiply this number by 2 (as the distance the ball travels upwards is equal to the distance travelled downwards) to get the total distance travelled.
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    (Original post by Mist786)
    ....
    TI-84's answers would be correct if the stone returned to the same level it was thrown from, however it does not.

    For part a) you know s = -3, u = 16, a = -9.8 (or whatever value you have been given) and you want to find t.

    So which equation involves those 4 quantities?

    For b) you can do what TI-84 suggested to find how far up it goes before coming to a stop. When coming down it will travel 3 metres further, and just add the two to get the total distance travelled.
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