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    In doing a pulley experiment, can i work out the mechanical advantage of each pulley as the load mass/effort mass?
    The effort being the weight added onto the other end of the string to lift the load.

    The traditional formula is input force/output force

    Thanks!
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    You will get the right answer!
    Strictly speaking, MA is measured with reference to the forces, but of course in this case it is the weight of the two masses that is acting, so the ratio of Load/Effort is Mg/mg and the g cancels, leaving you with just the masses.
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    (Original post by Stonebridge)
    You will get the right answer!
    Strictly speaking, MA is measured with reference to the forces, but of course in this case it is the weight of the two masses that is acting, so the ratio of Load/Effort is Mg/mg and the g cancels, leaving you with just the masses.
    Yeah i thought this was the case and just needed to check
    Thanks!
 
 
 
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