Hi guys. I'm stuck in the following problem:
a square hoop ABCD is made of smooth wire and has sides of length 2a. The hoop is horizontal and is rotating with constant angular speed w about a vertical axis through A. A small bead which can slide on the wire is initially on rest at the midpoint of BC. Choose axes fixed relative to the hoop, and let y be the distance of the bead from the vertex B on the side BC. Write down the position vector of the bead in the rotating frame.
I've chosen as axes AD=i, AB=j and AD x AB=k. In these axes we have w=(0,0,w), r(0)= (sqrt(5), (1/2)*sqrt(5), 0). But I don't know how to continue. Can anyone help me?
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Dynamics - rotating frames watch
- Thread Starter
- 10-02-2010 15:47