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# compicated fraction watch

1. Hi, im trying to a bit of proof by mathematical induction (such fun...)
I've got to a stage with this nasty looking fraction:

k(k+1)(2k+7)+6(k+1)(k+3)
---------------------------------------
6

i.e. (k(k+1)(2k+7)+6(k+1)(k+3)) over 6
or (k(k+1)(2k+7)+6(k+1)(k+3)) / 6
or (k(k+1)(2k+7)+6(k+1)(k+3)) divided by 6

My question is this:
Does the 6 on top cancel out the 6 on the bottom to give:

k(k+1)(2k+7)+(k+1)(k+3)

2. No. You would have to have a 6 in front of the k(k+1)(2k+7) term as well.
3. If you split up the fraction, you'd have to alter both of them in that case.
4. (Original post by monkeau)
Does the 6 on top cancel out the 6 on the bottom to give:

k(k+1)(2k+7)+(k+1)(k+3)

.

It would have only given If it was or .

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Updated: February 10, 2010
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