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# Titrations Question. watch

1. Equation:

H2X + 2NaOH > Na2X + H2O

24.1 ml of 0.104 moldm-3 sodium hydroxide neutralised 25 ml of the unknown acid. The acid was made up by dissolving 1.58g of crystal into 250 ml of water.

What is the RMM of the acid?

Sorry for the poor formatting and what not. No clue how to do subscript and superscript.

Thanks.
2. Calculate the number of moles of NaOH needed, and then you know the molar ration is 1:2

So half the number you get. Work out the amount of water in the acid and therefore the amount of crystal, and then work out the Mr of the crystal by doing mass/number of moles
3. I get 126. Anyone know if that's right?
4. (Original post by porkstein)
H2X + 2NaOH > Na2X + H2O

24.1 ml of 0.104 moldm-3 sodium hydroxide neutralised 25 ml of the unknown acid. The acid was made up by dissolving 1.58g of crystal into 250 ml of water.

What is the RMM of the acid?I get 126. Anyone know if that's right?
mol NaOH = 0.00251

Therefore moles of acid = 0.00125

in 250ml = 0.0125

so RMM of acid = 1.58/0.0125 = 126

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Updated: February 11, 2010
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