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Core 4 help
Hi,
On a bit of work i've got to do, theres a question mainly based on binomial expansion and the last part of the question i am not sure what to do.
Here is the question:
(a) Find the binomial expansion of (1+x)^(1/3) up to the term in x^2
(b) Show that (8+3x)^(1/3) ≈ 2 + 1/4 x -1/32 x^2 for small values of x
(c) Hence show that ∛9 ≈ 599/288
For part (a) i got 1 + 1/3 x - 1/9 x^2 and for part (b) i got the answer that it required but i haven't got a clue how to do (c)
Any help would be appreciated
Thanks
On a bit of work i've got to do, theres a question mainly based on binomial expansion and the last part of the question i am not sure what to do.
Here is the question:
(a) Find the binomial expansion of (1+x)^(1/3) up to the term in x^2
(b) Show that (8+3x)^(1/3) ≈ 2 + 1/4 x -1/32 x^2 for small values of x
(c) Hence show that ∛9 ≈ 599/288
For part (a) i got 1 + 1/3 x - 1/9 x^2 and for part (b) i got the answer that it required but i haven't got a clue how to do (c)
Any help would be appreciated
Thanks
Put x=1/3 in (b)
Let 8 3x = 9
Solve for x x = 1/3
Sub back into binomial expansion
2 + (1/4)(1/3)x (1/32)(1/3)^2
=599/288
Solve for x x = 1/3
Sub back into binomial expansion
2 + (1/4)(1/3)x (1/32)(1/3)^2
=599/288
Original post by kaprice ricot
Let 8 3x = 9
Solve for x x = 1/3
Sub back into binomial expansion
2 + (1/4)(1/3)x (1/32)(1/3)^2
=599/288
Solve for x x = 1/3
Sub back into binomial expansion
2 + (1/4)(1/3)x (1/32)(1/3)^2
=599/288
You're replying to a thread that is 10 years old! I think the OP is sorted by now
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can someone please explain what principle domain is and why the answer is a not c?Maths
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