I am doing c4 parametric equations.
dx/dy has come out as -3sint. When I replace t with the value given, I get -3/2. The reciprical obviously gives 2/3
Can I then just manipulate the equation of a straight line?
Instead of using y-y1= x (x-x1) can I just use x-x1 = y (y-y1) ?
Or is that not how it works?
I have tried reversing -3sint in order to get dy/dx but it doesn't give me the right answer.
c4 - dx/dy - finding equation of normal watch
- Thread Starter
- 11-02-2010 21:47
- 11-02-2010 21:53
isnt dx/dy simply 1/(dy/dx)? for example say you had gradient :-2 for the tangent, so for the normal it becomes 1/2, so dx/dy = 1/(1/2) which is 2.
(Original post by RedGold)
- 11-02-2010 22:45
dx/dy has come out as -3sint