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# Algebra problem - help needed please watch

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1. Hey, not sure how to work out this question.

a) Factorise 5x^2 + 6xy + y^2
b) Hence, write 50601 as a product of two integers both of which are greater than 5.

I can do a) easily. I get (x+y)(5x+y).

But I'm not sure about b).

Obviously it'll be (x+y)(5x+y) = 50601. But I don't know how to carry on from here

2. Write 5x^2 + 6xy + y^2 = 50601 and see what you can spot.
3. (Original post by yusufu)
Write 5x^2 + 6xy + y^2 = 50601 and see what you can spot.
Well it's a quadratic in terms of x (or y), so I suppose I could find x in terms of y or vice-versa. But that doesn't help, does it?
4. (Original post by gyyy2807)
Well it's a quadratic in terms of x (or y), so I suppose I could find x in terms of y or vice-versa. But that doesn't help, does it?
5x^2 + 6xy + y^2 = 50601 = 50000 + 600 + 1

Does that help?
5. (Original post by yusufu)
5x^2 + 6xy + y^2 = 50601 = 50000 + 600 + 1

Does that help?
ah ha I see now Thanks a lot
6. (Original post by yusufu)
5x^2 + 6xy + y^2 = 50601 = 50000 + 600 + 1

Does that help?
that would mean that x = 100 and y = 1

but the question says that both integers have to be greater than 5. so that wouldn't work.

Edit: sorry, problem solved. Thanks again
7. (Original post by gyyy2807)
that would mean that x = 100 and y = 1

but the question says that both integers have to be greater than 5. so that wouldn't work.
Are you allowed to use a calculator/know the prime compostition of 50601?
8. (Original post by JAKstriked)
Are you allowed to use a calculator/know the prime compostition of 50601?
not allowed calculator. No I don't know the prime composition of 50601.
9. (Original post by gyyy2807)
not allowed calculator. No I don't know the prime composition of 50601.
edit: Steve is right.

I guess we're both guilty of not reading the question!
10. (Original post by gyyy2807)
that would mean that x = 100 and y = 1

but the question says that both integers have to be greater than 5. so that wouldn't work.

Both numbers are over 5
11. (Original post by steve2005)

Both numbers are over 5
holy ****. yeah. somehow I thought x and y had to be over 5.

Thanks
12. (Original post by JAKstriked)
edit: Steve is right.

I guess we're both guilty of not reading the question!
yeah. silly mistake to make. Thanks for trying anyway
13. very interesting question!!!!!

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