The Student Room Group
Reply 1
arctanroot3=60
It's one of those angles that you should know.
sec60=1/cos60=1/0.5=2
Reply 2
JChoudhry
arctanroot3=60
It's one of those angles that you should know.
sec60=1/cos60=1/0.5=2


Oh I see. Thanks genius! :wink:
JChoudhry
arctanroot3=60
It's one of those angles that you should know.
sec60=1/cos60=1/0.5=2

This.

Or alternatively:

sec[arctan(3)]=xsec[arctan(\sqrt{3})]=x
sec2[arctan(3)]=x2sec^{2}[arctan(\sqrt{3})]=x^2
1+tan2[arctan(3)]=x21 + tan^{2}[arctan(\sqrt{3})]=x^2

Solve for x

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