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    If anyone could show me how how to work out a question such as this, it would be really helpful.



     2x +3y = 10

     \frac {2}{x} + \frac {3}{y} = 5
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    2x+3y=10 => x= (10-3y)/2

    sub into below equation, then multiply up by y or ysquared and get a disguised quadratic. could be wrong
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    If you multiply the second equation by xy then the solutions will still be the same (unless you get x=0 or y=0 as a result, in which case leave it out... can you see why?)
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    (Original post by Shakaa)
    If anyone could show me how how to work out a question such as this, it would be really helpful.



     2x +3y = 10

     \frac {2}{x} + \frac {3}{y} = 5
    I would multiply the equation with the fractions by xy
 
 
 
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Updated: February 12, 2010
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