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    The general solution for both (primary values,secondary values) of sintheta
    is given by :\theta\

=(-1)^nPV+n\pi .PV=primary value
    Although I can see why this is true from a cast diagram .does anyone know how to prove this?

    Thanks
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    (Original post by rbnphlp)
    The general solution for both (primary values,secondary values) of sintheta
    is given by :\theta\

=(-1)^nPV+n\pi .PV=primary value
    Although I can see why this is true from a cast diagram .does anyone know how to prove this?

    Thanks
    From the symmetry of the sine graph? Alternatively, prove that  \sin PV = \sin ((-1)^nPV + n\pi)
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    (Original post by Unbounded)
    From the symmetry of the sine graph? Alternatively, prove that  \sin PV = \sin ((-1)^nPV + n\pi)
    I think I found what I was looking for .Thanks anyway
 
 
 
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