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# Edexcel Maths C3 watch

1. (Original post by MyMathsAndScienceTutor)
Hi, I can't find Arsey's answers to C3 June 2010. It is usually a great help to see the paper and I'm sure we are all always very grateful to Arsey. Can anyone point me to the answers post? Thank you (!).
here it is.
http://www.thestudentroom.co.uk/show...&postcount=369
2. (Original post by Arsey)
126 should be fine

7d 2marks lost

1 mark on the other one I would think
Arsey are you sure?
I gave the time 206 and 403 in minutes will I get full marks for that question, then.
3. thanks for the mark scheme!
much appreciated
4. (Original post by jiyp)
thanks for the mark scheme!
much appreciated
How much are you getting?
5. (Original post by Arsey)
i think 67 will be nailed on for an A
Hi Arsey

Im new to TSR and just saw your mark scheme... I was wondering if you could tell me how many marks I have lost.

For part 1b) i did not see the 2 and so solved for tan=1.
For the range question i wrote y>=-3
And for the time question i did not get the second time.

Any help would be good-- also could you let me know what you think my likely ums is becuase i need an A*

Thanks.
6. (Original post by Arsey)
Module Session 100 90 80 (A) 70 (B) 60 (C) 50 (D) 40 (E)
C4 Jun-05 66 59 52 45 38 32 26
C4 Jan-06 75 68 61 53 45 38 31
C4 Jun-06 74 66 58 50 42 35 28
C4 Jan-07 72 65 58 51 44 37 31
C4 Jun-07 74 66 58 50 43 36 29
C4 Jan-08 67 61 55 49 43 37 31
C4 Jun-08 71 64 57 50 44 38 32
C4 Jan-09 73 66 59 52 45 38 32
C4 Jun-09 70 64 58 52 46 40 35
C4 Jan-10 75 68 61 53 46 39 32
and the award for the most helpful TSR user goes to. . .
lol, cheers arsey
7. (Original post by Arsey)
potentially you could lose 2 accuracy marks for the coordinates

you will lose at lease 2 marks for the time qu

do you mean >= -3; if so you should lose just 1 mark if the working was clear.

Yeah i meant >=-3 sorry
haha bet you'd be annoyed if people were arguing that it was just >-3 after jan
8. Anything better than 90 UMS will mean this re-take was worth it for me...

I can find only really two mistakes I've made, on 7d only;

1) Didn't find the second time
2) Didn't convert the time I got (126 minutes) in to the time after mid-day (i.e. 14:06). That's frankly ridiculous if that's worth a mark. Why at C3 level should we awarded a mark for added minutes onto a 24-hour clock? We've been doing that since KS1. I just forgot to do it ;_;.
9. (Original post by Pegasus92)
Arsey are you sure?
I gave the time 206 and 403 in minutes will I get full marks for that question, then.
2hrs 6min is fine

206mins isn't fine as it is incorrect

2:06 is fine pm will be assumed
10. (Original post by stock_wizard)
Hi Arsey

Im new to TSR and just saw your mark scheme... I was wondering if you could tell me how many marks I have lost.

For part 1b) i did not see the 2 and so solved for tan=1.
For the range question i wrote y>=-3
And for the time question i did not get the second time.

Any help would be good-- also could you let me know what you think my likely ums is becuase i need an A*

Thanks.
these seem like the big 3 errors

lose 2 marks
lose 1 mark
lose 2 marks (could be 3)

so 5 or 6 marks lost; this should be around 90UMS.
11. I was an idiot and got alpha wrong in the first part, but if my method was right throughout the question do i get error carried forward ?
12. (Original post by Arsey)
these seem like the big 3 errors

lose 2 marks
lose 1 mark
lose 2 marks (could be 3)

so 5 or 6 marks lost; this should be around 90UMS.

For the time one (missing out the second solution) surely this would only lose 1 mark because you would gain the method marks for working out the first time and the an answer mark for the 14:06 but you will lose a final answer mark because you did not state the last time?
13. I reckon i got 68 or 69/75 depending on whether the examiner will accept 'The inverse won't be a function as it'll have a square root and so cannot be a function'.

I reckon that'll be 91 UMS?

What do you think Arsey?
14. (Original post by stock_wizard)

For the time one (missing out the second solution) surely this would only lose 1 mark because you would gain the method marks for working out the first time and the an answer mark for the 14:06 but you will lose a final answer mark because you did not state the last time?
It will almost certainly be

M1 - pi - answer to get second angle for 4pi t / 25 + whatever it was

A1 A1 for the 2 answers

So I am pretty certain you'll lose 2 marks.
15. (Original post by chaz1992)
I reckon i got 68 or 69/75 depending on whether the examiner will accept 'The inverse won't be a function as it'll have a square root and so cannot be a function'.

I reckon that'll be 91 UMS?

What do you think Arsey?
Almost every candidate I have spoken to found it easier than expected. I think this was significantly more difficult than June 09 which was 67/75 for an A

Worst case scenario would be 65 - 80UM and 70 - 90UMS

My guess would be 63 - 80UMS; 69 - 90UMS
16. Only thing I reckon I did wrong was not putting time as in after midday , but wrote 126 and 403 minutes.. It was said that there's a chance it won't cost me a mark, wanted more opinions about this? It would be really great if I get 100 UMS in this paper, as I doubt for an easy paper as this one you could get 74/75 and still get 100 UMS =S
17. I somehow managed to work out R wrong and used that value throughout the whole of the question on no.7. Do you reckon I would lose all marks for that or get ecf or something?

Thanks
18. (Original post by omg123)
I somehow managed to work out R wrong and used that value throughout the whole of the question on no.7. Do you reckon I would lose all marks for that or get ecf or something?

Thanks
You might get some error carried forward marks.
19. (Original post by Arsey)
Almost every candidate I have spoken to found it easier than expected. I think this was significantly more difficult than June 09 which was 67/75 for an A

Worst case scenario would be 65 - 80UM and 70 - 90UMS

My guess would be 63 - 80UMS; 69 - 90UMS
I dropped about 17 marks in this exam, really silly errors, soo 58/75, how many ums do you reckon this would be?
20. Hi! I've just joined TSR and your mark scheme is really useful! I was just wondering whether you thought I'd lose marks because, on question 8, instead of factorising I did it like long division and ended up with 2 + (5x + 25)/(x^2 +2x-15) and then factorised so I ended up with 2 + 5/(x-3)...I wasn't sure if that was a wrong method or if we were allowed to use that? Thank you!

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