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    (Original post by Jamo1991)
    http://www.scribd.com/doc/33782843


    tell me of any changes i should make
    Why is 12
    7/8 and not 1/8?
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    (Original post by Pegasus92)
    Why is 12
    7/8 and not 1/8?
    because it asks for the fraction of the atoms that WILL have decayed, so 7/8 will have decayed, i think anyway :yep:
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    (Original post by Jamo1991)
    because it asks for the fraction of the atoms that WILL have decayed, so 7/8 will have decayed, i think anyway :yep:
    How many marks is that part?
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    (Original post by Pegasus92)
    How many marks is that part?
    2 so i guess you would get 1 for 1/8
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    (Original post by Jamo1991)
    2 so i guess you would get 1 for 1/8
    ohh I lose 1 more mark then
    Why dnt your upload the marking scheme on TSR?
    attachement.
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    (Original post by Jamo1991)
    No problem

    Tell me what you think of it and if I need to change anything
    others seem ok.
    How much are you expecting?
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    (Original post by Pegasus92)
    ohh I lose 1 more mark then
    Why dnt your upload the marking scheme on TSR?
    attachement.
    How do i do that?

    others seem ok.
    How much are you expecting?
    Erm hopefully at least 60/80 .... maximum i think i could get would be 67/80 but not too sure, how about you?
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    (Original post by Pegasus92)
    others seem ok.
    How much are you expecting?
    hey pegasus,i am here.
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    (Original post by Jamo1991)
    How do i do that?



    Erm hopefully at least 60/80 .... maximum i think i could get would be 67/80 but not too sure, how about you?
    Me too, in that range.
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    (Original post by fredbraty)
    hey pegasus,i am here.
    The unofficial marking scheme has been posted, so do we have to discuss?
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    People i am making an unofficial mark scheme right now.

    It will be posted tomorrow!

    :yep:

    :cool: :cool:
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    (Original post by Pegasus92)
    The unofficial marking scheme has been posted, so do we have to discuss?
    oh ok i will make one alone then :p:
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    (Original post by fredbraty)
    oh ok i will make one alone then :p:
    ok, Ill be there in a minute.
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    (Original post by Pegasus92)
    ok, Ill be there in a minute.
    Hey if you dont want,its fine
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    (Original post by fredbraty)
    Hey if you dont want,its fine
    No probs, I'm jobless.
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    I'm looking at like 57/80. Can I manage to get a B with this mark?

    In the last question, I didn't notice that 35 mm could be used as displacement so I started using energy considerations until the very end where I read the paragraph on the previous page and saw the 70 mm thing. Here's what I did, is it right?

    PE at maximum displacement = KE at zero displacement

    \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2

    a=w^2x => F=kx => F = kx = mw^2x

    k=mw^2

    \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 => \dfrac{1}{2}mw^2x^2=\dfrac{1}{2}  mv^2

    w^2x.x=v^2

    ax=v^2

    V being max. speed, a=0.89 and x=35 mm

    v=\sqrt{0.89*0.035}
    v=0.176
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    (Original post by Pegasus92)
    No probs, I'm jobless.
    Fb now
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    (Original post by Doughboy)
    I'm looking at like 57/80. Can I manage to get a B with this mark?

    In the last question, I didn't notice that 35 mm could be used as displacement so I started using energy considerations until the very end where I read the paragraph on the previous page and saw the 70 mm thing. Here's what I did, is it right?

    PE at maximum displacement = KE at zero displacement

    \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2

    a=w^2x => F=kx => F = kx = mw^2x

    k=mw^2

    \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 => \dfrac{1}{2}mw^2x^2=\dfrac{1}{2}  mv^2

    w^2x.x=v^2

    ax=v^2

    V being max. speed, a=0.89 and x=35 mm

    v=\sqrt{0.89*0.035}
    v=0.176
    As to Jays prediction, you might get an A with that mark, but who knows you may get better.
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    (Original post by fredbraty)
    Fb now
    ok, Ill come.
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    A few bits I'm not sure about:

    On the question asking about explaining why movement of stars relative to background stars is observed, would these three points be correct?
    - This is parallax; objects further away appear to move more slowly
    - The background stars are so far away that they appear not to be moving at all
    - As a result the background stars' motion can be considered negligible and so are used as a reference point for nearby stars.

    On the question about explaining how a radioisotope's activity in the body can be detected, would it count to say that it is a tracer and it emits radioactive radiation which can be detected by a Geiger counter?

    Overall I think I could get about 70/80 for this paper.
 
 
 
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