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    (Original post by foolsihboy)
    It was =/
    LOLOLOL.

    Honestly that must have been painful. Surely you only finished half an hour ago then?
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    (Original post by IchiCC)
    Does anyone know how they do the UMS scale?

    Because I think I did well in the actual paper, but messed up a bit in the comprehension.

    Do they add the two raw marks together then convert to UMS, or do they work out a UMS for each paper separately, then add them together?
    Combine then convert to UMS
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    (Original post by Skadoosh)
    Vector questions:

    ii) to find the angle between the vertical and direction vector, I'm fairly sure you had to use a vertical direction such that (0,0,z) where z is any positive number as it was the line OZ. No matter what value for z you used, you'd notice that when finding costheta, the two values of z should cancel anyway.

    iv) last part; you find the angle between normal direction to the plane and direction of AB. I then took this value away from 90degrees.

    Again, not 100% on these, but I'm fairly certain they're right.
    i did the same
    apart from the last part i added 90degrees - again not sure!
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    It was really weird that ratio thing.

    Knowing the values of C and A you then had to sub these into the x=2theta - sintheta

    and then i did someting like OC-OA = AC

    And using value for OA which was pi - 1 and then AC was pi + 1
    and that was it
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    (Original post by -5-6-7-)
    it cant be those values because it said OA and OB had a ratio of pi-1i+1
    which is effectively 1:2
    i got B is pi
    and A is pi/2

    however my working didnt really make sense, so ive no idea how i got that
    i duno if its right but it makes sense?
    I just did Length OA= pi-1
    Length AB= 2pi-OA
    =2pi-(pi-1)
    =pi+1
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    (Original post by -5-6-7-)
    it cant be those values because it said OA and OB had a ratio of pi-1i+1
    which is effectively 1:2
    i got B is pi
    and A is pi/2

    however my working didnt really make sense, so ive no idea how i got that
    i duno if its right but it makes sense?
    I got the same parameter values!
    I think for A, I put y=0 and got θ = pi/2
    and for B, went on the basis that the cos graph has a minimum when cosθ=-1 and which would make θ = pi. Dunno if that's right?
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    (Original post by morrison11)
    I did 180-angle. Though I wasn't sure it was necessary, so I did it in kinda small writing.
    I did that. No sure whether its right though.
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    (Original post by Miss_Chanel)
    I got the same parameter values!
    I think for A, I put y=0 and got θ = pi/2
    and for B, went on the basis that the cos graph has a minimum when cosθ=-1 and which would make θ = pi. Dunno if that's right?
    yep that was my method of working too! not sure how i get there i dont get parametric equations but the values fitted
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    (Original post by Miss_Chanel)
    So do you remember what you got as the answer?
    I think I used the same method and got roughly 72 degrees - anyone else?
    Yeah I used (0,0,100) and got about 72 degrees. What did the people who used (0,0,1) get.

    Other than Q3 I thought it was OK. Comprehension was good imo.

    What did people get for that tan(theta+45) question. Q6 I think it was.
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    (Original post by The Stig's student cousin)
    Yeah I used (0,0,100) and got about 72 degrees. What did the people who used (0,0,1) get.

    Other than Q3 I thought it was OK. Comprehension was good imo.

    What did people get for that tan(theta+45) question. Q6 I think it was.
    I used (0, 0, 1) and got 72 degrees, same direction vector, but the calculations are slightly easier with (0, 0, 1).
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    Also what did people say for why Jenny was wrong? I said the trapezium rule gives an overestimate so using more strips would give a smaller value than the one in part (i) but I thought when a curve was increasing in gradient (as it was) the trapezium rule gave an underestimate.
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    (Original post by morrison11)
    You've forgotten metres there..
    i did all 3
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    (Original post by DeanT)
    I used (0, 0, 1) and got 72 degrees, same direction vector, but the calculations are slightly easier with (0, 0, 1).
    Cool, thanks.
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    (Original post by GenericStudent)
    For the partial fractions question, did A=1 and B=-1? Because I swear I messed something up round there..
    Thats what I got, and I think that's right
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    (Original post by Miss_Chanel)
    So do you remember what you got as the answer?
    I think I used the same method and got roughly 72 degrees - anyone else?
    I got 72 as well, yes.

    --

    I took the angle away from 90 for the plane question, with a little diagram much like the one posted before.
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    (Original post by -5-6-7-)
    it cant be those values because it said OA and OB had a ratio of pi-1i+1
    which is effectively 1:2
    i got B is pi
    and A is pi/2

    however my working didnt really make sense, so ive no idea how i got that
    i duno if its right but it makes sense?
    how i did somehow manage to make it fit that ratio, when i put the values into the x equation. took me forever though!
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    Yeah the partial fractions were A = 1, B = -1. I almost got caught out in the second part of that question, nearly forgot to multiply both sides by 3. If they didn't show the answer you needed I probably would have got that wrong :p:
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    (Original post by The Stig's student cousin)
    Yeah I used (0,0,100) and got about 72 degrees. What did the people who used (0,0,1) get.

    Other than Q3 I thought it was OK. Comprehension was good imo.

    What did people get for that tan(theta+45) question. Q6 I think it was.
    erm, i got 0, and another answer, like 62 or something
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    (Original post by Scabo0o)
    Thats what I got, and I think that's right
    It had to be right, otherwise you couldnt do the second part, which incidentally I didn't see until I was half way through Q7, luckily I started Q6 on another page and had quite a bit of room under part (i) so glad I spotted it because it was an easy 5marks
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    (Original post by The Stig's student cousin)
    Also what did people say for why Jenny was wrong? I said the trapezium rule gives an overestimate so using more strips would give a smaller value than the one in part (i) but I thought when a curve was increasing in gradient (as it was) the trapezium rule gave an underestimate.
    http://www.mei.org.uk/files/papers/c407ja_1jd8q.pdf

    take a look at question 2!

    p.s. love your username!
 
 
 
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