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# Simple integration question watch

1. (Original post by student92)
Hey, i got another question... if u could help me: find dy/dx of 3/x-2 - 2/x+3 when x is -1. The answer is 1/6 but i keep getting -1/6
1/6 is correct.

Try rewriting 3/x-2 as 3(x-2)^-1 and the same with the other term. See if you can go from there.
2. (Original post by Hippysnake)
1/6 is correct.

Try rewriting 3/x-2 as 3(x-2)^1 and the same with the other term. See if you can go from there.
3/(x-2) =
3. (Original post by JamesyB)
Have you rewitten it as and used the chain rule?
yes
4. (Original post by student92)
yes
Have you checked to make sure all your signs are correct?
5. (Original post by Hippysnake)
1/6 is correct.

Try rewriting 3/x-2 as 3(x-2)^-1 and the same with the other term. See if you can go from there.
i have rewritten it like that... after differentiating i get: 3(x-2 )^-2 - 2(x+3)^-2
6. (Original post by student92)
i have rewritten it like that... after differentiating i get: 3(x-2 )^-2 - 2(x+3)^-2
Sure it's '-2' and not '+2'?

if you differentiate

-2(x+3)^-1 you get

-1*-2(x+3)^-1
which is +2(x+3)^-2
7. (Original post by Hippysnake)
Sure it's '-2' and not '+2'?

if you differentiate

-2(x+3)^-1 you get

-1*-2(x+3)^-1
which is +2(x+3)^-1
This is not correct. The answer is

8. (Original post by steve2005)
This is not correct. The answer is

I think I'll just keep to myself....I got the right answer on paper, just forgot to put the -2 term up.

Ah well, OP probably figured out how to do it on her own anyway.
9. (Original post by student92)
Hey, how would you work this out: The integral of 4 / 2x - 3 between the limits x is 6 and 2?

.

I've an exam on this few days to go. I hope you guys don't mind me solving an already solved question for practice. Haha.

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