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# Log help - again watch

1. How would I start to solve this question:

Log-to-the-base-2 (x) + log-to-the-base-4 (x) =2

Thanks
2. (Original post by ian.slater)
\log_a b = {\log_c b \over \log_c a}
well that failed - but you need to use a log identity that you might be able to figure out from this junk
3. Better know as changing the base...
4. Use the change of base formula.
5. You should find x = 4. Unless I myself have done something wrong.
6. (Original post by Futurdoc)
You should find x = 4. Unless I myself have done something wrong.
Sub your value back into the original equation and see what you get (or don't get!).
7. 2 + 1 doesn't equal 2. Now I'm confused

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